Find the smallest natural number that we need to divide 243 with to make it a perfect square
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Let us prime factorise 243 first.
243 = 3×3×3×3×3
We can see that there are 5 3s in its prime factorisation.
We need to arrange the prime factors into pairs.
We observe that 2 such pairs can be formed and one 3 is left behind.
So the smallest number by which 243 needs to be divided is 3.
243÷3 = 81 ( 9² )
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Answer:
here is ur ans dear ☺️
We observe that 2 such pairs can be formed and one 3 is left behind. So the smallest number by which 243 needs to be divided is 3.
Step-by-step explanation:
hope it's helpful for you ❤️
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