Question

Find the smallest natural number which when divided by 16,24and36 leaves remainder 4in each case

Answer 1

Answer:

The smallest number which divides 12 16 24 and 36 is 144. But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (144+7=151). Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 7 is 151

Answer 2

Concept:

Natural numbers are those positive numbers that start from 1 and go till infinity.

Given:

We have, 16, 24, and 36 as divisors,

and 4 as the remainder.

Find:

We are asked to find the smallest natural number.

Solution:

So,

To find the smallest natural number,

First take the LCM of 16, 24, and 36.

LCM (16, 24, 36) = 144

Now,

We have to find that number which leaves the remainder 4,

So,

Add 4 to LCM of 16, 24, and 36,

i.e. 144+4 = 148

Hence, the smallest natural number is 148.

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