Math, asked by mahichaudhary4812, 9 months ago

find the smallest natural number which when divided by 18 35 36 and 70 leaves remainder 7 in each case

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Answered by roopeshamaltp

Answer:

Next add 7 to 7980 to get 7987 as the answer. Check: 7987 divided by 20 = 399 as quotient and a remainder of 7. ... Now, N divided by 20, 42 or 76 leaves remainder 7 inneach case.

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find the smallest natural number which when divided by 18 35 36 and 70 leaves remainder 7 in each case​

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find the smallest natural number which when divided by 18 35 36 and 70 leaves remainder 7 in each case