Math, asked by stusayujyars011783, 1 day ago

Find the smallest natural number which when divided by 24, 18 ,40 and 60 leaves reminder 8in each case

Answers

Answered by izabelapinto77
0

Step-by-step explanation:

Factors of

24 = 2x2x2x3

18 = 2x3x3

40 = 2x2x2x5

60 = 2x2x3x5

LCM = 2x2x2x3x3x5 = 360

360+8 = 368.

Answer is 368.

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