Question

Find the smallest natural number, which when divided by 3, leaves a remainder 2; when divided by 5, leaves a remainder 4; and when divided by 7, leaves a remainder 5.

Answer 1

Answer:

1) 6/3=2

2) 20/5=4

3) 35/7=5

so your answers are 6,20,35

hopes it will help you.........

Answer 2

Answer:

First of all

it's given that when no. is divided by 3 or 5 it leaves remainder 2 and 4 respectively

that mean required no. must be 1 less than the LCM and multiple of LCM

LCM of 3 and 5= 15

possible no= 15-1,30-1,45-1,60-1,75-1,90-1

now check which no. will give remainder 5 when devided by 7

it will be 89

ans = 89