Question

Find the smallest no. by which 2560 must be multi plied so that the product is aperfect cube.(sameer)

Answer 1

Answer:

given no. =2560 . expressing into prime factors , we have

2560= 2×2×2×2×2×2×2×2×2×5. Since 5 left unpaired. to make perfect cube , we should multiply 5×5=25. 2560×25=64000. which is a perfect cube . hence the smallestno. by which 2560 must be multiplied so that the product is perfect cube is = 5×5=25.