Question

Find the smallest no by which 3645 must be
divided so that it becomes a perfect square.
Also find the square root of the resulting
no.​

Answer 1

Answer:

the correct answer is 5.and it will come √729=27 . please mark me as brainalist.

Answer 2

Take LCM of 3645

$= 5 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3$

hence

$= (5) \times (3 \times 3) \times( 3 \times 3) \times ( 3 \times 3)$

hence 5 is only unpaired no.

$thus \: if \: we \: divide \\ \: 3645 \: by \: 5 \: the \: the \\ \: no \: obtained \: will \: be \\ \: a \: perfect \: square \\ \frac{3645}{5} = \frac{5 \times 729}{5} = 729 \\ \sqrt{729} = 27$