Find the smallest no by which 3645 should be divided so that quotient is perfect cube
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Given number is 3645
Jot down the prime factors of 3645
3645=5*3*3*3*3*3*3
Organising the prime factors into pairs
3645=(3*3)(3*3)(3*3)*5
We observe that only 5 doesnt exist in pair
So,the smallest number that should be divided from 3645 to make it a perfect square is 5
3645÷5= 729
Thus the resulting number is 729
√729=27
There fore , 27 is the square root of resulting number 729
Read more on Brainly.in - https://brainly.in/question/1193056#readmore
Jot down the prime factors of 3645
3645=5*3*3*3*3*3*3
Organising the prime factors into pairs
3645=(3*3)(3*3)(3*3)*5
We observe that only 5 doesnt exist in pair
So,the smallest number that should be divided from 3645 to make it a perfect square is 5
3645÷5= 729
Thus the resulting number is 729
√729=27
There fore , 27 is the square root of resulting number 729
Read more on Brainly.in - https://brainly.in/question/1193056#readmore
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