Find the smallest no. by which 8640 must be divided so that the quotient is a perfect cube?
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by prime factorisation process:
8640÷2=4320
4320÷2=2160
2160÷2=1080
1080÷2=540
540÷2=270
270÷3=90
90÷3=30
30÷3=10
10÷2=5
5÷5=1
therefore 2×5=10
no 10 should be divided
8640÷10=864
864 is a perfect cube
8640÷2=4320
4320÷2=2160
2160÷2=1080
1080÷2=540
540÷2=270
270÷3=90
90÷3=30
30÷3=10
10÷2=5
5÷5=1
therefore 2×5=10
no 10 should be divided
8640÷10=864
864 is a perfect cube
AashikYasmin:
thank u
welcome...but is it correct?
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