Question

Find the smallest no. by which 9408 must be divided to make it a perfect square. Also find the square root of no. so obtained.​

Answer 1

Out of the prime factors of 9408, only 3 is without pair. So, 3 is the number by which 9408 must be divided to make the quotient a perfect square. pls mark as brainliest :)

Answer 2

Answer:

Step-by-step explanation:

We have 9408=    2×2   ×  2×2   ×  2×2   ×3×  7×7

​

 If we divide 9408 by the factor 3 then  

9408÷3=3136=  2×2   ×  2×2   ×  2×2   ×  7×7

​  which is a perfect square (why ?)  

And  

3136    =2×2×2×7=56