Question

find the smallest no. by which 943 must be multiplied to obtain a perfect cube​

Answer 1

$Resolving \: 943 \:into \: prime \: factors,$

$we \: get$

943 = 21 × 43

The prime factor 21 and 43 does not appear in a group of three.

So, 943 is not a perfect cube .

Hence, the smallest number by which it is to be multiplied to make it a perfect cube is 21×21 × 43 × 43 = 815409

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