Question

find the smallest no which divides 20,25,50 leaving a remainder of 9​

Answer 1

Answer:

109

Step-by-step explanation:

Smallest number which is divisible by 20, 25 and 50 will be their LCM which is 100.

So the smallest number which divides by 20 25 50 leaving remainder 9​ will be

100 + 9 = 109

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