find the smallest no which is divided by 28 and 32 leaves remainder 8and 12 respectively
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Soln:
28-8=20 & 32-12=20
So the reqd no will be 20 less than the L. C. M. of 28 and 32 .
L. C. M. of 28 & 32 is = 224
Reqd smallest no =224-20 = 204.
Soln:
28-8=20 & 32-12=20
So the reqd no will be 20 less than the L. C. M. of 28 and 32 .
L. C. M. of 28 & 32 is = 224
Reqd smallest no =224-20 = 204.
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