Find the smallest no. which when divided by 18, 12 and 24 leaves a remainder of 16, 10 and 22 respectively.
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now, you see that the difference between 18, 12, 24 and 16, 10, 22 respectively is 2. so the number which when divided by these numbers to get the latter numbers is 70. so that this number is 2 numbers away from being completely divisible in each case and leaves remainders 16, 10, 22 respectively.
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