Math, asked by Singamaneni14, 1 year ago

Find the smallest no. which when divided by 18, 12 and 24 leaves a remainder of 16, 10 and 22 respectively.

Please answer in detail and step-by-step...

Answers

Answered by Anonymous
1

Answer:

hope it will help you!!!

Step-by-step explanation:

2

now, you see that the difference between 18, 12, 24 and 16, 10, 22 respectively is 2. so the number which when divided by these numbers to get the latter numbers is 70. so that this number is 2 numbers away from being completely divisible in each case and leaves remainders 16, 10, 22 respectively.

Answered by Anonymous
5

➪ \sf \red{Answer:-}

 \huge{ ➫} \tt GIVEN:-

length \: of \: room \:  = 7m25cm = 725cm \\ breadth \: of \: room \:  = 9m25cm = 925cm \\ height \: of \: room \:  = 8m25cm = 825cm

\huge ➫ \sf FIND:-

now \: we \: find \: HCF \: of \: 725,925 \: and \: 825

{\huge ➫  {\mathfrak{Solution:-}}}

725 = 5 \times 5 \times29

925 = 5 \times 5 \times 37

825 = 3 \times 5 \times 5 \times 11

so, \: heighest \: common \: factor \: is \: 5 \times 5 = 25

therefore \: HCF \: of \: 725,925,825 \: is \: 25.

\therefore 25m is \:  the  \: longest \:  tape \:  measure \:  which  \: can  \: measure \:  all  \: the  \: dimensions.

so, \: answer \: is \:  \boxed{ \mathbf{ 25m}}

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