Math, asked by paramjit387, 5 hours ago

find the smallest no which when divided by 35,36 and 105 leaves a remainder of 6 in each case?

Answers

Answered by Revanasiddeshpatil

0

Answer:

5880

Step-by-step explanation:

The smallest number which when divided by 35, 56 and 105= LCM(35,56,105)

35=5×7

56=2

3

×7

105=21×5

LCM=2³×5×7×21=5880

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