Math, asked by khusboorongpee, 8 months ago

find the smallest no. which when divided by 35,56 and 91 leaves remainder 7 in each case​

Answers

Answered by adisri082234
0

Answer:

3647

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.

Answered by mohdirshad51242
0

Answer:

8689 8587 she will be hello

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