Question

find the smallest no which when increased by 17 is exactly divisible by both 520 and 468

Answer 1

Lcm of 520 = 2^3 * 5 * 13

Lcm of 468 = 2^2 * 3^2 * 13

Lcm of 520 and 468 = 2^3 * 3^2 * 5 * 13

                                   = 4680

Smallest number = 4680 - 17

                             = 4663


Hope this helps!