Math, asked by sriharsha2837, 1 year ago

Find the smallest no which when increased by 27 is exactly divisible by 660 and 594

Answers

Answered by avhibunty

Let the number be "x"

LCM Of 660 and 594 will be 1980.

According to the question..

x=(LCM of 660and594) - 27
x= 1980-27
x=1953
I think you have understand.
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