Question

Find the smallest no. which when increased by 5 becomes divisible by 12, 15 and 20

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Factors of 12, 18 and 30

⇒ 12 = 2 × 2 × 3

⇒ 18 = 2 × 3 × 3

⇒ 30 = 2 × 3 × 5

⇒ L.C.M. of 12, 18 and 30 = 180

⇒ Required number = 180 – 5 = 175

∴ Required number is 175.

Step-by-step explanation:

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