Find the smallest nuber which when divded by 25,40and 60 leaves remainder 7 in each case
Answers
Answered by
2
L.C.M of 25, 40 and 60
25= 5×5
40=5×2×2×2
60=5×3×2×2
L.C.M =5×5×2×2×2×3
= 60
therefore, the smallest no. when divided by 25 , 40 and 60 lives remainder 7( 600+7) that is 607.
25= 5×5
40=5×2×2×2
60=5×3×2×2
L.C.M =5×5×2×2×2×3
= 60
therefore, the smallest no. when divided by 25 , 40 and 60 lives remainder 7( 600+7) that is 607.
Similar questions