find the smallest number 2560 must be multiplied so that the product become a perfect cube also find the cube root of resulting number
Answers
Answered by
6
Answer:given no = 2560
expressing into prime factors ,we have 2560 = (2×2×2)×(2×2×2)×(2×2×2)×(5×-×-)
since 5 left unpaired . to make perfect cube , we should multiplied 5
5×5=25
2560×25 = 64000
perfect cube of 64000 = (2×2×2)×(2×2×2)×(2×2×2)×(5×5×5)
=2^3 × 2^3 × 2^3 × 5^3
cube root of 64000 =2×2×2×5
=40
Answered by
0
Answer:
answer is 40
Step-by-step explanation:
Similar questions