Question

Find the smallest number 4 digit number, when divided by 7, 9 and 11 leaves a remainder of 3, 5 and 7 in each case.​

Answer 1

Answer:

We can do every answer easy if we understand the concept

The answer is 344

The procedure is down

Step-by-step explanation:

Let the number be p

P/7 => remainder 1

P/9 => remainder 2

P/11 => remainder 3

2P/7 => remainder 2

2P/9 => remainder 4

2P/11 => remainder 6

Notice that if we add 5 to 2P , these equation will become completely divisible by 7,9 and 11 respectively, i.e. remainder becomes 0.

2P+5/7 => remainder 0

2P+5/9 => remainder 0

2P+5/11 => remainder 0

this means 2P+5 is divisible by 7,9 & 11. So it will be divisible by 7x9x11=693

2P+5=693

2P= 688

P=344