Find the smallest number by which 1100 must be divided so that the quotient became a perfect square. Also find the squares root of the perfect square so obtained?
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Answered by
12
We can use prime factorisation method to do it
1100=2×2×5×5×11
11 is left out so we will have to divide 11 to make 1100 a perfect square. And the quotient will be 2×2×5×5 or 1100/11 which will be 100 and it's square root is 2×5 as 2 and 5 are grouped. So it's square root is 10
1100=2×2×5×5×11
11 is left out so we will have to divide 11 to make 1100 a perfect square. And the quotient will be 2×2×5×5 or 1100/11 which will be 100 and it's square root is 2×5 as 2 and 5 are grouped. So it's square root is 10
Answered by
18
Here is your answer⤵️
Prime factors of 1100 = 2×2×5×5×11
11 is the only number left.
So 11 is the number which must be divided 1100 to make is a perfect square.
1100÷11 is 100
100 = 2×2×5×5
= 100
The square root of 100 is 10
Prime factors of 1100 = 2×2×5×5×11
11 is the only number left.
So 11 is the number which must be divided 1100 to make is a perfect square.
1100÷11 is 100
100 = 2×2×5×5
= 100
The square root of 100 is 10
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