Find the smallest number by which 128 must be divided to obtain a perfect cube.
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Answered by
57
128
128 = (2 x 2 x 2) x (2 x 2 x 2) x 2
Here, one 2 is left which does not form a triplet.
If we divide128 by 2 , then it will become a perfect cube
128/2 = (2 x 2 x 2) x (2 x 2 x 2) x 2/2
64= (2 x 2 x 2) x (2 x 2 x 2) is a perfect cube.
Hence, the smallest number by which 128 should be divided to make it a perfect cube is 2.
Answered by
3
Answer:
2
Step-by-step explanation:
128 / 2 = 64
As we know 8 square = 64
And 4 cube = 64
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