find the smallest number by which 2008 should be multiied to make it a perfect square
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2008
Prime factors
2x2x2x251
Pairing
(2x2)x2x251
2 and 251 are not paired so the least no. by which it should be multiplied by is...
2x251
=502
Number
2008x502
=1,008,016
Root of 1,008,016
2x2x251
=1004
Prime factors
2x2x2x251
Pairing
(2x2)x2x251
2 and 251 are not paired so the least no. by which it should be multiplied by is...
2x251
=502
Number
2008x502
=1,008,016
Root of 1,008,016
2x2x251
=1004
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