Find the smallest number by which 243 must be divided to obtain a perfect cube
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The prime factor 3 is not a group of three. ∴ 243 is not a perfect cube. Now, 729 becomes a perfect cube. Thus, the smallest required number to multiply 243 to make it a perfect cube is 3.
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Now, 729 becomes a perfect cube. Thus, the smallest required number to multiply 243 to make it a perfect cube is 3. Grouping the prime factors of 256 in triples, we are left over with 2 × 2.
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