Question

Find the smallest number by which 252 must be multiplied to get a perfect square also find the square root of the perfect square so obtained

Answer 1

[ first of all, we need to bring the prime factors of 252 by prime factorisation method ]

Prime factors of 252
= 2×2×3×3×7

[ as, 7 is not in pair like "2×2" & "3×3" ]
So, smallest number to be multiplied
= 7

[ multiply 7 to the digits ]

$252 \times 7 = 2 \times 2 \times 3 \times 3 \times 7 \times 7 \\ \\ \: \: \: \: \: \: \: 1764 = \sqrt{2 \times 2 \times 3 \times 3 \times 7 \times 7 } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times 3 \times7 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 42$

Perfect sq. = 1764

Sq. root of perfect sq. = 42

Answer 2

Answer:

7

Step-by-step explanation:

find the factors of 252 by prime factorization and then 7 will be the number who has no pair soo that means 252×7 will be ur answer hope it helped give this answer a like and heart ;D