Find the smallest number by which 256 0 must be multiplied so that the product become a perfect cube
hamanya:
You should be do this positively as it was in my paper
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Maybe it can come in your paper
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Answered by
3
we have to prime factorize 2560.
2 / 2560
2 / 1280
2 / 640
2 / 320
2 / 160
2 / 80
2 / 40
2 / 20
2 / 10
5 / 5
/ 1.
now as you can see, all 2s can be grouped into groups of three. however, 5 does not have a group. so to make this number a cube, we will have to multiply the original number by 5x5, as we lack a group of three for 5 but we have one 5. ∴, the number that 2560 should be multiplied with to make a perfect square is 5x5 = 25.
2 / 2560
2 / 1280
2 / 640
2 / 320
2 / 160
2 / 80
2 / 40
2 / 20
2 / 10
5 / 5
/ 1.
now as you can see, all 2s can be grouped into groups of three. however, 5 does not have a group. so to make this number a cube, we will have to multiply the original number by 5x5, as we lack a group of three for 5 but we have one 5. ∴, the number that 2560 should be multiplied with to make a perfect square is 5x5 = 25.
Answered by
0
2560 * 1.6 = 4096 = 16 * 16 * 16 = 16^3
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