Math, asked by kahkasa, 11 months ago

find the smallest number by which 2560 be multipled so that the product is a perfect cube ...


Answers

Answered by shrushtti
3

take prime factor of 2560

2560=2×2×2×2×2×2×2×2×2×5

the product has 3 sets of 2^3 and a 5

clearly to make it a perfect cube it must be multiplied by 5×5 i.e. 25

Answered by brunoconti
2

Answer:

Step-by-step explanation:

since

2560 = 8^3 × 5

then by multiplying by 25 we get

2560 × 25 = 8^3 × 5^3 = (8 × 5)^3

= 40^3.

the smallest number by which 2560 should be multiplied to get a perfekt cube is 25.

Similar questions