find the smallest number by which 2560 be multipled so that the product is a perfect cube ...
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take prime factor of 2560
2560=2×2×2×2×2×2×2×2×2×5
the product has 3 sets of 2^3 and a 5
clearly to make it a perfect cube it must be multiplied by 5×5 i.e. 25
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Answer:
Step-by-step explanation:
since
2560 = 8^3 × 5
then by multiplying by 25 we get
2560 × 25 = 8^3 × 5^3 = (8 × 5)^3
= 40^3.
the smallest number by which 2560 should be multiplied to get a perfekt cube is 25.
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