Find the smallest number by which 2560 must be divided so that the product will be a Perfect cube
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2 is the smallest number by which it divide
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2560 = 5×2×2×2×8×8
Since 5 is not in pairs of three , hence we divide the number by 5 so that every number left is in pair and the number obtained is a perfect cube
We can check it too
Dividing by 5, we get
512 which is a perfect cube of 8
Here is your answer
Hope it helps
Thank u ★★★
#ckc
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Since 5 is not in pairs of three , hence we divide the number by 5 so that every number left is in pair and the number obtained is a perfect cube
We can check it too
Dividing by 5, we get
512 which is a perfect cube of 8
Here is your answer
Hope it helps
Thank u ★★★
#ckc
Plz mark brainiest if right
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