Find the smallest number by which 2560 must be divided to make it a perfect square. Also find the square root of the new number obtained.
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given no = 2560
expressing into prime factors ,we have 2560 = 2×2×2×2×2×2×2×2×2×5 . since 5 left unpaired . to make perfect cube , we should multiplied 5×5=25 .2560×25 = 64000. which is a perfect cube. hence the smallest no by which 2560 must be multiplied so that product is perfect cube = 5×5=25.
expressing into prime factors ,we have 2560 = 2×2×2×2×2×2×2×2×2×5 . since 5 left unpaired . to make perfect cube , we should multiplied 5×5=25 .2560×25 = 64000. which is a perfect cube. hence the smallest no by which 2560 must be multiplied so that product is perfect cube = 5×5=25.
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Answer:
we should divide 2560 by 5
Step-by-step explanation:
So
because 5×5 =25
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