Question

find the smallest number by which 2560 must be multipled so that the product is a perfect


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Answer 1

Answer:

given no = 2560 .

expressing into prime factors ,we have 2560 = 2×2×2×2×2×2×2×2×2×5 .

since 5 left unpaired . to make perfect cube , we should multiplied 5×5=25 .2560×25 = 64000. which is a perfect cube.

hence the smallest no by which 2560 must be multiplied so that product is perfect cube = 5×5=25.