Find the smallest number by which 2560 must be multiplied so that the product a perfect cube
Answers
Answered by
0
Step-by-step explanation:
2560= 8^3 *5. If we multiply the number by 5^2=25, the result will be 8^3* 5^3, which is the perfect cube. So 25 is the smallest positive integer
Answered by
0
Answer:
we try to find by prime factorisation
step by step explaination
\sqrt[3]{2560 }
2560=
2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5
clearly for making cube must be multiply by
5 \times 5
= 25
both side
2560 \times 25 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5 \times 5 \times 5
hence,
64060=2560 .
ans. = smallest number is 25
Step-by-step explanation:
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