Question

find the smallest number by which 2560 must be multiplied so that the profit perfect is a perfect cube

Answer 1

hye

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aim:to Find the smallest number by which 2560 must be multiplied so that the profit perfect is a perfect cube

first let us do prime factorisation of 2560

=>2560 =  2*2*2*2*2*2*2*2*2*5

=> (2*2*2*2*2*2*2*2*2*5) can be written as

=> 2² *2²*2² *2² *2*5

we see that 2 and 5 are not in pair

=>2*5=10

∴10 is the number  by which 2560 must be multiplied so that the profit perfect is a perfect cube

=>2560 *20 =25600

=>√25600 = 160

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hope it helps u...........

Answer 2

so to get the perfect cub root we must multiplied by 25
   2560 x 25 = 64000
then cube root of 64000 = 40 is the solution

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