find the smallest number by which 2560 must be multiplied so that the product becomes a perfect cube
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For this first we have to find its factors and make the pair of three.The factors are 2^9 ×5 . the 5 is alone and not making pair as it wants two multiples of 5 to make the pair of three so the smallest number is 5×5=25.
I HOPE IT HELPS U.
HERE IS UR ANSWER.
Thanks for asking this question.
For this first we have to find its factors and make the pair of three.The factors are 2^9 ×5 . the 5 is alone and not making pair as it wants two multiples of 5 to make the pair of three so the smallest number is 5×5=25.
I HOPE IT HELPS U.
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