find the smallest number by which 289 must be multiplied to obtain a perfect cube?also find the cube root of the number so obtained
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Answer:
Step-by-step explanation:
(v) 7803
First find the prime factors of 7803
7803 = 3 × 3 × 3 × 17 × 17
= 33 × 172
Since 7803 is not a perfect cube.
To make the quotient a perfect cube we divide it by 17^2 = 289, which gives 27 as quotient and we know that 27 is a perfect cube
∴ 289 is the required smallest number.
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