find the smallest number by which 2940 must be multiplied so that it becomes a perfect square
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write 2940 as product of primes
2940 = 2*2*3*5*7*7
= (2*2)*(7*7)*2*3
2 and 3 are isolated numbers
so , to make 2940 perfect square ,we have to multiply it with 2*3
2940*2*3 = (2*2)*(7*7)*(2*2)*(3*3)
17640 =(2*7*2*3)²
= (84)²
2940 = 2*2*3*5*7*7
= (2*2)*(7*7)*2*3
2 and 3 are isolated numbers
so , to make 2940 perfect square ,we have to multiply it with 2*3
2940*2*3 = (2*2)*(7*7)*(2*2)*(3*3)
17640 =(2*7*2*3)²
= (84)²
Answered by
2
Answer:
(84)²
Step-by-step explanation:
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