Math, asked by AlanDrake, 5 months ago

FIND THE SMALLEST NUMBER BY WHICH 297 TO BE DIVIDED TO GET A PERFECT CUBE . ALSO FIND OUT THE CUBE ROOT OF SO OBTAINED NUMBER .​

Answers

Answered by Pallavipundir0023
1

Answer:

Here is ur solution :-

Step-by-step explanation:

By resolving 81 into prime factors

297 = 3×3×3×11

By grouping the factors in triplets of equal,

297 =(3×3×3)×11

Here, 11 can not be grouped into triplets of equal factors.

Thus we will divide 297 by 11 to get perfect square.

That is 297÷11 = 27

Now new no. is 27 so the cube root of 27 :-

prime factorisation of 27 = (3×3×3)

= 3

Therefor the Cube Root of 27 = 3

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