Question

Find the smallest number by which 3645 must be divided so that it becomes a perfect square. Also find the square root of resulting number.

Please Answer

Answer 1

Hey there !
I am praneeth from brainly benefecator team,hope i will be helpful .

Given number is 3645
Jot down the prime factors of 3645
3645=5*3*3*3*3*3*3

Organising the prime factors into pairs

3645=(3*3)(3*3)(3*3)*5

We observe that only 5 doesnt exist in pair

So,the smallest number that should be divided from 3645 to make it a perfect square is 5

3645÷5= 729

Thus the resulting number is 729

√729=27

There fore , 27 is the square root of resulting number 729

hope helped!

-Regards ,
Praneeth,
Brainly benefecator.

Answer 2

Hi,
To find the smallest no. by which 3645 must be divided to become a perfect sq. we have to find prime factors of the no.
3645=3×3×3×3×3×3×5
so,
their is 3pair of 3.but no pair of 5.
so we have to divide the no. by 5 to have a perfect square.
if we will divide it by 5 we will obtain the sq.of 27(729).