find the smallest number by which 3645 must be divided so that it become a perfect square also find the square root of the resulting number
Answers
Answered by
10
HEY DEAR . ✌
___________________________
Given number is 3645
Jot down the prime factors of 3645
3645=5*3*3*3*3*3*3
Organising the prime factors into pairs
3645=(3*3)(3*3)(3*3)*5
We observe that only 5 doesnt exist in pair
So,the smallest number that should be divided from 3645 to make it a perfect square is 5
3645÷5= 729
Thus the resulting number is 729
√729=27
There fore , 27 is the square root of resulting number 729
HOPE , IT HELPS .
FOLLOW ME . ✌
___________________________
Given number is 3645
Jot down the prime factors of 3645
3645=5*3*3*3*3*3*3
Organising the prime factors into pairs
3645=(3*3)(3*3)(3*3)*5
We observe that only 5 doesnt exist in pair
So,the smallest number that should be divided from 3645 to make it a perfect square is 5
3645÷5= 729
Thus the resulting number is 729
√729=27
There fore , 27 is the square root of resulting number 729
HOPE , IT HELPS .
FOLLOW ME . ✌
ankit597:
wow
Answered by
4
Hello dear Ankit✌.
refer to the attachment
Attachments:
Similar questions