find the smallest number by which 3645 must be divided so that it becomes a perfect square also find the square root of the resulting number
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3645 = 3*3*3*3*3*3*5
= (3^2)*(3^2)*(3^2)*5
As, 5 is not in pair so, the smallest number by which 3645 should be divided to make it a perfect square is 5.
So, the square root of the resulting number is____
Math.sqrt(3645/5)
= Math.sqrt(729)
= Math.sqrt(3*3*3*3*3*3)
= 3*3*3
= 27
Answered by
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Answer:3645/5=729
Square root of 729 =27
Step-by-step explanation:
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