Question

find the smallest number by which 4068 must be divided to make it a perfect square also find the number whose square is the resulting number​

Answer 1

On prime factorisation of this no. we get

$4068 = {2}^{2} \times {3}^{2} \times 113$

So it must be divided by 113 to get a perfect square.

And the resulting number is 36 which is the square of 6

Answer 2

$\mathfrak{Answer}$

Prime factorisation of 4068 = $\tt{2^{2} \times 3^{2} \times 113}$

Divide this number by 113, you get = 36

36 is the square of 6