Question

find the smallest number by which 441 must be multipley so that product s perfect cube

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Answer 1

Answer:

by the prime factorisation of 441

√441 = 21

21 remained in the prime factorisation of 441

smallest no. = 441 ×21 = 9261

and by prime factorisation of 9261 = 21×21×21 =21

because we want perfect cube

Step-by-step explanation: