Find the smallest number by which 500 must be divided to obtain a perfect cube. Also, find the
cube root of the cubic number thus obtained.
Answers
Step-by-step explanation:
A perfect cube should have all of its ‘factors’ occurring in groups of 3.
So, let’s factor 500.
2 * 2 * 5 * 5 * 5
Wow! The only factor that doesn’t occur in a group of 3 is 2. So, we would add one more factor of 2 to get 2 * 2 * 2 * 5 * 5 * 5 = 1000 which happens to be 10 cubed.
So, the answer to your question is 2.
All cube numbers must have factors in groups of 3,
Let us first factorise 500
2 | 500 500 = 2 x 2 x 5 x 5 x 5
2 | 250 Here, the number 2 only has a pair and not a triplet
5 | 125 As we are asked in the question to divied 500 to get a
5 | 25 perfect cube, we shall remove the pair of 2s,
5 | 5 2 x 2 = 4
1 500/4 = 125
125 = 5³