find the smallest number by which 65100 should be divided to get a perfect cube.
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the prime factorization of 65100 =
2 x 2 x 3 x 5 x 5 x 7 x 31
and none of digit have the pair of 3 hence the smallest no by which it should divide is 65100
which will give
65100/65100 = 2 x 2 x 3 x 5 x 5 x 7 x 31 /65100
1 cube = 1*1*1 = 1
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