find the smallest number by which 6912 must be divided to obtain a perfect cube
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3 is the smallest number by which 6912 must be divided
tushi88:
hii
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6912= 2×2×2×2×2×2×2×2×3×3 ×3
=(2×2)(2×2)(2×2)(2×2)(3×3)×3
=(2×2)^4 × (3×3)^1 × 3
now, required number will be 4,
6912 / 4 = 1728
1728 = ( 12 )^3
1728 is a perfect cube of 12 .
therefore ,
the smallest required number is 4.
=(2×2)(2×2)(2×2)(2×2)(3×3)×3
=(2×2)^4 × (3×3)^1 × 3
now, required number will be 4,
6912 / 4 = 1728
1728 = ( 12 )^3
1728 is a perfect cube of 12 .
therefore ,
the smallest required number is 4.
now check
you were asking me , recently i saw your question
but u gave wrong answer
you gave me answer of square
i corrected it , check it again
answer is 4
for cube
check solution again , i explained it for cube . hope it helps now
thank you
welcome
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