Question

Find the smallest number by which 81920 must be divided to obtain the perfect cube

Answer 1

Hi !!!

Here is your answer,

81920 = 2×2×2×2×2×2×2×2×2×2×2×2×2×2×5

We observe that the prime factor 5 does not form a pair.

Therefore, we must divide the number 5 so that the quotient becomes perfect square.

81920÷5 = 16984

16984 = 2×2×2×2×2×2×2×2×2×2×2×2×2×2

Now, each prime factor occurs in pairs. Therefore the required smallest number is 5

16984 = 2×2×2×2×2×2×2 = 128


Hope it helps.

Answer 2

Answer:

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