find the smallest number by which 8640 must be divided so that the quotientis a perfect cube
Answers
Answered by
10
prime factorization of 8640 = 2 * 2 * 2 * 2 * 2 * 2 * 3 * 3 * 3 * 5
= 2^3 * 3^3 * 5.
In order to make it a perfect cube, it must be divided by 5.
Verification :
8640/5 = 1728(12^3) is a perfect cube.
So, the smallest number is 5.
Hope this helps!
= 2^3 * 3^3 * 5.
In order to make it a perfect cube, it must be divided by 5.
Verification :
8640/5 = 1728(12^3) is a perfect cube.
So, the smallest number is 5.
Hope this helps!
Similar questions