find the smallest number by which 8640 must be divided so that the quotient is a perfect cube ?
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Answered by
164
8640 = 2*2*2*2*2*2*3*3*3*5 = (2*2*2)*(2*2*2)*(3*3*3)*(5)
to make it perfect cube, it should be divided by 5
to make it perfect cube, it should be divided by 5
kvnmurty:
check
edited
Answered by
59
PRIME FACTORIZATION OF 8640 :
8640=[2x2] [2x2] [2x2] [3x3] [3] x[5]
To make it a perfect cube we should divide it with 5
ps: our teachers are killing us with home work are'nt they???
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