Find the smallest number by which 8640 must be divided so that the quotient is a perfect cube?
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Hey there !
Solution:
8640 can be made a perfect cube by dividing it by a quotient. That quotient can be found out by using Prime Factorisation method.
8640 = 2^6 × 3^3 × 5
So if the 5 is not there then the number would become a perfect cube.
Hence the number must be divided by 5.
So the perfect cube we get is 8640 / 5 = 1728 which is 12^3.
Hope my answer helped !
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